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tAnxy y

limx趋于2y趋于0,tan(xy)/y=sin(xy)/{cos(xy)*y},sin(xy)=xy,cos(xy)=1,原式=xy/y*1=x=2,(x趋于2y趋于0,xy相当于y趋于0)

a这是是一个三维矩阵,a(:,:,1)表示取a矩阵第一页的所有行和列。 三维矩阵中第一维为行,第二维为列,第三维为页; matlab中矩阵用:表示取该维度的所有下标值。

数学应该是多做多练习,练习足够了自然而然就会了,依靠别人解答是不明智的做法,别人做的终究是别人会,而你还是不会。好好加油吧!

lim tan(xy)/y,(x->3,y->0)的极限怎么求啊! 解: lim tan(xy)/y,(x->3,y->0) =lim xy/y(x->3,y->0) =limx (x->3,y->0) =3

tanxy/y 有括号吧 (tanxy)/y =……=1

lim(x,y→0,0) tan(xy)/(xy) = lim(x,y→0,0) sin(xy)/(xy) • 1/cos(xy) = 1 • 1 = 1

对x求导得到 [tan(xy)]' =1/[cos(xy)]^2 *(xy)' =1/[cos(xy)]^2 * (x' *y +x*y') =1/[cos(xy)]^2 * (y +x*y') 若知道x和y的关系再代入计算y' 即可

y'=[tan(xy)]' =sec²(xy)·(xy)' =sec²(xy)·(y+xy') =sec²(xy)·y+sec²(xy)·x·y' =sec²(xy)·tan(xy)+sec²(xy)·x·y' [1-sec²(xy)·x]y'=sec²(xy)·tan(xy) y'=sec²(xy)·tan(xy)/[1-sec²(xy)·x]

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